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March 31, 2015

March 31, 2015

Posted by **Hannah** on Thursday, August 30, 2012 at 10:27pm.

To start off I had to use the micrometer to find the diameter D(mm) of the steel ball. 5 trials were completed. For the first trial I got 15.90 mm. The volume V=1/6(pi)D^3 had to be calculated next so to do this I plugged 15.9 into the equation 1/6(3.14)(15.90^3) and got 2019. For each trial I plugged my D value into the equation and then to calculate the average Volume I added all the numbers up and divided by 5.

So far before I continue can you please tell me if I did this correctly. Thank you for your help!!

- Physics(Please help, thank you) -
**Elena**, Friday, August 31, 2012 at 4:09am1. Find the average magnitude of diameter

(D1+D2+D3+D4+D5)/5 ={D}

2. ΔD1 =|{D}-D1|

ΔD2=|{D}-D2|

…

ΔD5 =|{D}-D5|

Average absolute error is

{ΔD}= (ΔD1+,,,+ ΔD5)/5.

3. The relative error is {ΔD}/{D}

4. Since V~D³ the error of your result = 3• {ΔD}/{D}.

If you want it in %, multiply by 100.

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