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Landing with a speed of 78.3 m/s, and traveling due south, a jet comes to rest in 959 m. Assuming the jet slows with constant acceleration, find the magnitude and direction of its acceleration.

  • physics -

    a=[v²(fin)-v²(init)]/2•s= - 78.3²/2•959 = = -3.2 m/s².
    "a "is opposite to the velocity, i.e., to the north.

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