can anyone help me please convert
water is flowing through a-inchdiameter pipe with a velocity of 3FT/S. WHAT IS the KE of water in (ft) (lbf)/lbm
To calculate the kinetic energy (KE) of water in ft-lbf/lbm, we need to use the formula:
KE = (1/2) * m * v^2
where KE is the kinetic energy, m is the mass of water, and v is the velocity of water.
To find the mass of water, we need to know the volume flowing per second. Since we know the velocity and diameter of the pipe, we can calculate the cross-sectional area of the pipe using the formula:
A = π * (d/2)^2
where A is the cross-sectional area, and d is the diameter of the pipe.
Now, we can find the volume of water flowing per second by multiplying the cross-sectional area by the velocity:
V = A * v
Next, we need to find the mass of water flowing per second. The density of water is approximately 62.4 lbm/ft^3. We can calculate the mass using the formula:
m = V * ρ
where m is the mass, V is the volume, and ρ is the density.
Finally, we can plug the values into the kinetic energy formula to calculate KE in ft-lbf/lbm.
Now, let's calculate the kinetic energy of water:
1. Determine the pipe's cross-sectional area:
A = π * (d/2)^2
A = π * (a/2)^2 [since "a" is the diameter]
2. Calculate the volume of water flowing per second:
V = A * v
V = (π * (a/2)^2) * 3 ft^3/s
3. Find the mass of water flowing per second:
m = V * ρ
m = (π * (a/2)^2) * 3 ft^3/s * 62.4 lbm/ft^3
4. Calculate the kinetic energy:
KE = (1/2) * m * v^2
KE = (1/2) * [(π * (a/2)^2) * 3 ft^3/s * 62.4 lbm/ft^3] * v^2
Note: Make sure to substitute the appropriate values for "a" (pipe diameter) and "v" (velocity) in the formula to get the final result of kinetic energy in ft-lbf/lbm.