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September 18, 2014

September 18, 2014

Posted by **Rebekah** on Thursday, August 30, 2012 at 2:01pm.

#1 Find the difference quotient of f foreach function

f(x)=1/(x+3)

I got -2x+6

#2 Express the area of an isosceles right triangle as a function of the length x of one of the two eual sides

Thanks

- pre calc -
**Steve**, Thursday, August 30, 2012 at 3:42pmThe difference quotient,

∆f/∆x = [f(x+h)-f(x)]/h

= [1/((x+h)+3) - 1/(x+3)]/h

= 1/h [(x+3) - (x+h+3)] / (x+h+3)(x+3)

= 1/h (-h)/(x+h+3)(x+3)

= -1/[(x+h+3)(x+3)]

The legs are x and x. One leg is the base, the other leg is the height, so the area is 1/2 bh = 1/2 x^2

Why can't the hypotenuse be one of the equal sides? Because the hypotenuse is longer than either leg.

- pre calc -
**Rebekah**, Thursday, August 30, 2012 at 5:49pmfor the second problem what is th height??

- pre calc -
**Rebekah**, Thursday, August 30, 2012 at 5:50pmohh wait ok that was me just having a dumb moment haha. THANKS sooo much:)

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