Posted by Rebekah on Thursday, August 30, 2012 at 2:01pm.
I have a few problems from my homework that I am having trouble with.
#1 Find the difference quotient of f foreach function
f(x)=1/(x+3)
I got 2x+6
#2 Express the area of an isosceles right triangle as a function of the length x of one of the two eual sides
Thanks

pre calc  Steve, Thursday, August 30, 2012 at 3:42pm
The difference quotient,
∆f/∆x = [f(x+h)f(x)]/h
= [1/((x+h)+3)  1/(x+3)]/h
= 1/h [(x+3)  (x+h+3)] / (x+h+3)(x+3)
= 1/h (h)/(x+h+3)(x+3)
= 1/[(x+h+3)(x+3)]
The legs are x and x. One leg is the base, the other leg is the height, so the area is 1/2 bh = 1/2 x^2
Why can't the hypotenuse be one of the equal sides? Because the hypotenuse is longer than either leg.

pre calc  Rebekah, Thursday, August 30, 2012 at 5:49pm
for the second problem what is th height??

pre calc  Rebekah, Thursday, August 30, 2012 at 5:50pm
ohh wait ok that was me just having a dumb moment haha. THANKS sooo much:)
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