Posted by Rebekah on Thursday, August 30, 2012 at 2:01pm.
The difference quotient,
∆f/∆x = [f(x+h)-f(x)]/h
= [1/((x+h)+3) - 1/(x+3)]/h
= 1/h [(x+3) - (x+h+3)] / (x+h+3)(x+3)
= 1/h (-h)/(x+h+3)(x+3)
= -1/[(x+h+3)(x+3)]
The legs are x and x. One leg is the base, the other leg is the height, so the area is 1/2 bh = 1/2 x^2
Why can't the hypotenuse be one of the equal sides? Because the hypotenuse is longer than either leg.
for the second problem what is th height??
ohh wait ok that was me just having a dumb moment haha. THANKS sooo much:)
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