Wednesday

July 23, 2014

July 23, 2014

Posted by **Megan** on Thursday, August 30, 2012 at 1:57pm.

A person standing outside their house is passed by a runner heading West at a steady pace of 3.3 m/s. Right when the runner passes by, the person accelerates towards the south at a rate of 0.36 m/s2 for 1.2 seconds. Determine how far apart the people are when t = 1.2 seconds.

I tried distance = 1/2at^2 but that did not work. Any help would be greatly appreaciated

- physics -
**Megan Lee**, Thursday, August 30, 2012 at 2:06pmI used the equation above since the initial velocity was 0 same goes for the initial distance. For some reason it is wrong.

- physics -
**bobpursley**, Thursday, August 30, 2012 at 3:17pmThey are traveling at right angles.

distance=sqrt(W^2+S^2) where W, S are the distances west, and south.

distanceW=3.3*1.2

distanceS=1/2 .36*1.2^2

solve for distance from the first relation above.

- physics -
**Henry**, Saturday, September 1, 2012 at 8:02pmpost it.

**Related Questions**

physics - This is the question to one of my physic problem. A person standing ...

Physics - Runner A is running at a constant rate of 2.3 m/s when he passes ...

math/physics - During a race, one runner runs at a 6 min/mi pace and another ...

physics - Runner A is running at a constant rate of 2.3 m/s when he passes ...

math - Two runners are competing in a race. One runner averages a pace of 7 ...

math - Two runners are competing in a race. One runner averages a pace of 7 ...

physics - In an 8.00 race, one runner runs at a steady 11.8 and another runs at ...

physics - A runner is jogging at a steady 2.3 km/hr. When the runner is 8.4 km ...

Physic - A person in a dark room looking through a window can clearly see a ...

Physics - You are keeping pace with another runner, at 4 minutes per mile, but ...