Posted by Unknown on Thursday, August 30, 2012 at 12:06pm.
Write an equation for the line in point/slope form and slope/intercept form that has the given condition.
4. Slope = 3/2 and passes through the origin.
5. x-intercept = 4 and y-intercept = -3
6. Passes through (3, 2) and is parallel to 2x-y=4
7. Passes through (-1, -1) and is perpendicular to y= (5)/(2)x+3
Algebra2 - Steve, Thursday, August 30, 2012 at 12:20pm
as you know, slope is ∆y/∆x
so, for any point (x,y) on the line containing (h,k) with slope m,
m = ∆y/∆x = (y-k)/(x-h)
or, as some like it,
y = m(x-h) + k
So, for #6,
2x-y = 4
y = 2x-4, so
slope is 2, so
(y-2) = 2(x-3)
y = 2x - 4
Do the others the same way. Com eon back if you get stuck. Be sure to show how you got there.
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