posted by Shaka .
Find, the nearest tenth, the area of the region that is inside the square and outside the circle. The diameter of the circle is 14in.
I assume you are referring to a circle inscribed in a square. If not, please clarify
the diameter of the circle is the same as the side of the square, 14 in.
area of circle = 49pi
area of square = 14^2 = 196
so, the difference is 196-49pi =~ 42in^2
a+b = the absolute value a + b