3x + 2iy =6 + 10i
3x = 6
x = 2
2y = 10
y = 5
satisfies the equation
To find the values of x and y in the equation 3x + 2iy = 6 + 10i, we need to separate the real and imaginary parts.
The given equation is in the form a + bi, where a is the real part and b is the imaginary part.
Comparing the equation 3x + 2iy = 6 + 10i with the form a + bi, we can equate the real parts and imaginary parts separately.
Equating the real parts:
3x = 6
Solving for x:
Divide both sides of the equation by 3:
3x/3 = 6/3
x = 2
Equating the imaginary parts:
2iy = 10i
Solving for y:
Divide both sides of the equation by 2i:
(2iy) / (2i) = 10i / (2i)
y = 10i / (2i)
y = 5
Therefore, the values of x and y that satisfy the equation 3x + 2iy = 6 + 10i are x = 2 and y = 5.