An object moves with constant acceleration 3.65 m/s2 and over a time interval reaches a final velocity of 10.4 m/s.
(a) If its initial velocity is 5.2 m/s, what is its displacement during the time interval?
(b) What is the distance it travels during this interval?
(c) If its initial velocity is
m/s, what is its displacement during the time interval?
(d) What is the total distance it travels during the interval in part (c)?
physics - Elena, Thursday, August 30, 2012 at 5:08am
Assume that positive x-axis directed to the right
t=( v-vₒ)/a=(10.4-5.2)/3.65=1.42 s
displacement = distance= vₒt+at²/2=5.2•1.42+3.65•1.42²/2=
7.384+3.68 =11.064 m
(from origin point - to theright)
s1 =vₒ²/2a=5.2²/2•3.65=3.7 m (to the left)
s2= at²/2=3.65•2.89²/2=15.23 m (to the right)
Distance=3.7 +15.23=18.93 m
Displacement =15.23-3.7=11.53 m