Posted by roger on Thursday, August 30, 2012 at 12:29am.
An object moves with constant acceleration 3.65 m/s2 and over a time interval reaches a final velocity of 10.4 m/s.
(a) If its initial velocity is 5.2 m/s, what is its displacement during the time interval?
m
(b) What is the distance it travels during this interval?
m
(c) If its initial velocity is
−5.2
m/s, what is its displacement during the time interval?
m
(d) What is the total distance it travels during the interval in part (c)?
m

physics  Elena, Thursday, August 30, 2012 at 5:08am
Assume that positive xaxis directed to the right
(a)(b) v=vₒ+at
t=( vvₒ)/a=(10.45.2)/3.65=1.42 s
displacement = distance= vₒt+at²/2=5.2•1.42+3.65•1.42²/2=
7.384+3.68 =11.064 m
(from origin point  to theright)
(c) v=vₒ+at
t1=(0+vₒ)/a=5.2/3.65=1.42 s.
s1 =vₒ²/2a=5.2²/2•3.65=3.7 m (to the left)
v=a•t2
t2=v/a=10.4/3.65=2.89 s.
s2= at²/2=3.65•2.89²/2=15.23 m (to the right)
Distance=3.7 +15.23=18.93 m
Displacement =15.233.7=11.53 m