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April 19, 2014

April 19, 2014

Posted by **Anonymous** on Wednesday, August 29, 2012 at 9:54pm.

- physic -
**Henry**, Friday, August 31, 2012 at 10:19pmTr = (Vf-Vo)/g = (0-12) / -9.8 = 1.22 s=

Rise time or time to reach max .ht.

hmax = ho + (Vf^2-Vo^2)/2g.

hmax = 24.4 + (0-144) / -19.6 = 31.75 m=

ht. above gnd.

h = Vo*t + 0.5g*t^2 = 31.75 m.

0 + 4.9t^2 = 31.75

t^2 = 6.48

Tf = 2.55 s. = Time to fall to gnd.

D = r*(Tr+Tf).

r = D/(Tr+Tf)

r=31.4 / (1.22+2.55) = 8.33 m/s.

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