Posted by **Sylvie** on Wednesday, August 29, 2012 at 7:14pm.

You and your friend live 12 miles apart. You leave home at the same time and travel toward each other. You walk at a rate of 4 mph and your friend bicycles at a rate of 11 mph. A) How long after you leave home will you meet? How far from home will each of you be? B) Suppose your friend bikes at a rate of 12 mph. How much sooner will you meet? How far from home will each of you be?

- Algebra -
**bobpursley**, Wednesday, August 29, 2012 at 7:28pm
let d be the distance you travel. So 12-d is the distance friend travels. You both pedal for time t (hrs)

d=4t

12-d=11t

add the equations. 12=15t t=12/15 hr

then find d, and 12-d from either equation.

- Algebra -
**Damon**, Wednesday, August 29, 2012 at 7:28pm
speed toward each other = 11+4 = 15 mph

so time = 12/15 = 4/5 hour = 48 minutes

4/5 * 4 = 16/5 = 3.2 miles

4/5* 11 = 44/5 = 8.8 miles

Now you should be able to do it with a different speed.

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