Posted by Unknown on .
a graph with the points (0,3) (2,4) (2,4)
What would be the domain, range xintercepts yintercepts and funtional value..
Help Please?..

Algebra2  incomplete 
Steve,
just given three points, there's no way to tell anything in general about the function. All we know is
the domain includes {2,0,2}
the range includes {4,3}
yintercept at y = 3
no xintercept given
there are many functions which contain these three points:
y = x/2  3
y = 1/2 cos(π/4 x)  3.5
y = cos(π/2 x)  3
y = x^2/4  3
y = 1/4 x^4  x^2  3
and so on 
Algebra2 
Unknown,
Thanks?..
Same Type of question...
cAn you tell me if these are maybe right?..
1. points of (2,2) (1,4) (2,6)
Domain:(4,2,6)
range:(2,2)
xIntercept: none
yIntercept: none
functional value: x^2+2 
Algebra2 
Steve,
domain: {1,2}
range: {2,4,6}
domain is the xcoordinate (1st value)
range is the ycoordinate (2nd value)
f(x) is certainly not x^2 + 2
(1)^2 + 2 = 3, not 4
(2,6) fits, but (2,2) does not.
In fact, since (2,2) and (2,6) contain the same xvalue, but different yvalues, these pairs are not even a function.