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Algebra2

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a graph with the points (0,-3) (2,-4) (-2,-4)

What would be the domain, range x-intercepts y-intercepts and funtional value..

Help Please?..

  • Algebra2 - incomplete - ,

    just given three points, there's no way to tell anything in general about the function. All we know is

    the domain includes {-2,0,2}
    the range includes {-4,-3}

    y-intercept at y = -3
    no x-intercept given

    there are many functions which contain these three points:

    y = -|x/2| - 3
    y = 1/2 cos(π/4 x) - 3.5
    y = cos(π/2 x) - 3
    y = -x^2/4 - 3
    y = 1/4 x^4 - x^2 - 3
    and so on

  • Algebra2 - ,

    Thanks?..
    Same Type of question...

    cAn you tell me if these are maybe right?..

    1. points of (2,2) (-1,4) (2,6)

    Domain:(-4,2,6)
    range:(2,2)
    xIntercept: none
    y-Intercept: none
    functional value: x^2+2

  • Algebra2 - ,

    domain: {-1,2}
    range: {2,4,6}
    domain is the x-coordinate (1st value)
    range is the y-coordinate (2nd value)

    f(x) is certainly not x^2 + 2
    (-1)^2 + 2 = 3, not 4
    (2,6) fits, but (2,2) does not.

    In fact, since (2,2) and (2,6) contain the same x-value, but different y-values, these pairs are not even a function.

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