Posted by Unknown on Wednesday, August 29, 2012 at 3:05pm.
a graph with the points (0,3) (2,4) (2,4)
What would be the domain, range xintercepts yintercepts and funtional value..
Help Please?..

Algebra2  incomplete  Steve, Wednesday, August 29, 2012 at 4:03pm
just given three points, there's no way to tell anything in general about the function. All we know is
the domain includes {2,0,2}
the range includes {4,3}
yintercept at y = 3
no xintercept given
there are many functions which contain these three points:
y = x/2  3
y = 1/2 cos(π/4 x)  3.5
y = cos(π/2 x)  3
y = x^2/4  3
y = 1/4 x^4  x^2  3
and so on

Algebra2  Unknown, Wednesday, August 29, 2012 at 4:55pm
Thanks?..
Same Type of question...
cAn you tell me if these are maybe right?..
1. points of (2,2) (1,4) (2,6)
Domain:(4,2,6)
range:(2,2)
xIntercept: none
yIntercept: none
functional value: x^2+2

Algebra2  Steve, Wednesday, August 29, 2012 at 5:25pm
domain: {1,2}
range: {2,4,6}
domain is the xcoordinate (1st value)
range is the ycoordinate (2nd value)
f(x) is certainly not x^2 + 2
(1)^2 + 2 = 3, not 4
(2,6) fits, but (2,2) does not.
In fact, since (2,2) and (2,6) contain the same xvalue, but different yvalues, these pairs are not even a function.
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