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August 29, 2014

August 29, 2014

Posted by **Unknown** on Wednesday, August 29, 2012 at 3:05pm.

What would be the domain, range x-intercepts y-intercepts and funtional value..

Help Please?..

- Algebra2 - incomplete -
**Steve**, Wednesday, August 29, 2012 at 4:03pmjust given three points, there's no way to tell anything in general about the function. All we know is

the domain includes {-2,0,2}

the range includes {-4,-3}

y-intercept at y = -3

no x-intercept given

there are many functions which contain these three points:

y = -|x/2| - 3

y = 1/2 cos(π/4 x) - 3.5

y = cos(π/2 x) - 3

y = -x^2/4 - 3

y = 1/4 x^4 - x^2 - 3

and so on

- Algebra2 -
**Unknown**, Wednesday, August 29, 2012 at 4:55pmThanks?..

Same Type of question...

cAn you tell me if these are maybe right?..

1. points of (2,2) (-1,4) (2,6)

Domain:(-4,2,6)

range:(2,2)

xIntercept: none

y-Intercept: none

functional value: x^2+2

- Algebra2 -
**Steve**, Wednesday, August 29, 2012 at 5:25pmdomain: {-1,2}

range: {2,4,6}

domain is the x-coordinate (1st value)

range is the y-coordinate (2nd value)

f(x) is certainly not x^2 + 2

(-1)^2 + 2 = 3, not 4

(2,6) fits, but (2,2) does not.

In fact, since (2,2) and (2,6) contain the same x-value, but different y-values, these pairs are not even a function.

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