The length of a rectangle mailing letter is 3cm less than twice the width.The perimeter is 30cm. Find the dimensions of the label(length and width).

2(2w-3 + w) = 30

w = 6

the letter is 6x9cm

To solve this problem, we can start by assigning variables to the dimensions of the rectangle. Let's say the width is 'w' cm.

According to the problem, the length of the rectangle is 3 cm less than twice the width. So we can express the length as 2w - 3 cm.

The perimeter of a rectangle is calculated by adding up all four sides. In this case, the perimeter is given as 30 cm.

The formula for the perimeter of a rectangle is:
Perimeter = 2 * (length + width)

Substituting the given information into the formula, we get:
30 = 2 * ((2w - 3) + w)

Now, let's solve for 'w':

30 = 2 * (3w - 3)

Divide both sides by 2:
15 = 3w - 3

Add 3 to both sides:
15 + 3 = 3w

18 = 3w

Divide both sides by 3:
6 = w

So, the width of the rectangle is 6 cm.

To find the length, we substitute the value of 'w' back into the expression for the length:

Length = 2w - 3
Length = 2 * 6 - 3
Length = 9 cm

Therefore, the dimensions of the rectangle are:
Width = 6 cm
Length = 9 cm