4. Is the following always, sometimes, or never true?
14 + 3x – 7 = 7x + 7 – 4x
14 + 3x – 7 = 7x + 7 – 4x
7 + 3x = 7 + 3x
0 = 0
It is ALWAYS true.
how can you write 52+(8+25)
To determine if the statement is always, sometimes, or never true, we can simplify the equation and compare the coefficients of x on both sides.
Starting with the given equation:
14 + 3x - 7 = 7x + 7 - 4x
Simplifying the left side:
14 + 3x - 7 = 7x + 7 - 4x
7 + 3x = 7x + 7 - 4x
7 + 3x = 3x + 7
Moving the variables to one side:
7 + 3x - 3x = 3x + 7 - 3x
7 = 7
Now, analyzing the equation 7 = 7, we can see that this equation is true. Therefore, the given equation is always true and holds for any value of x.
In conclusion, the equation 14 + 3x - 7 = 7x + 7 - 4x is always true.
To determine whether the given equation is always, sometimes, or never true, we need to simplify it and see if it simplifies to a true statement.
First, we can combine like terms on both sides of the equation. On the left-hand side:
14 + 3x - 7 simplifies to 7 + 3x.
On the right-hand side:
7x + 7 - 4x simplifies to 3x + 7.
Our equation now becomes:
7 + 3x = 3x + 7.
By examining the equation, we can see that both sides are identical. This means that the equation is true for all values of x, making it always true.
Therefore, the answer is: The equation 14 + 3x – 7 = 7x + 7 – 4x is always true.