mgco3 plus 2hcl plus mgci2 plus h2 h20 plus co2 if 10grames of c02 is produced calculate the mass of magnesium and hydrochoric acid reacted
To calculate the mass of magnesium (Mg) and hydrochloric acid (HCl) reacted, we need to use mole-to-mole ratios and the molar masses of the substances involved.
Based on the balanced chemical equation:
MgCO3 + 2HCl → MgCl2 + H2O + CO2
We see that the ratio between the moles of magnesium carbonate (MgCO3) and carbon dioxide (CO2) is 1:1. This means that if 1 mole of magnesium carbonate reacts, 1 mole of carbon dioxide is produced.
First, we need to determine the number of moles of carbon dioxide produced. We're given that 10 grams of carbon dioxide (CO2) is produced.
Step 1: Calculate the number of moles of CO2.
Mass of CO2 (molar mass) = 44 g/mol
Number of moles = Mass / Molar mass = 10 g / 44 g/mol ≈ 0.227 moles
Since the ratio between MgCO3 and CO2 is 1:1, the same number of moles will be used for both substances. So, 0.227 moles of magnesium carbonate (MgCO3) reacted.
Step 2: Calculate the mass of magnesium (Mg) reacted.
Molar mass of Mg = 24.31 g/mol
Mass of Mg = Number of moles × Molar mass = 0.227 moles × 24.31 g/mol ≈ 5.52 grams
Therefore, approximately 5.52 grams of magnesium reacted.
Step 3: Calculate the mass of hydrochloric acid (HCl) reacted.
Since the mole ratio between HCl and MgCO3 is 2:1 (2 moles of HCl react with 1 mole of MgCO3), we need to use half the number of moles of MgCO3 to find the number of moles of HCl.
Number of moles of HCl = (0.227 moles of MgCO3) / 2 = 0.1135 moles
Molar mass of HCl = 36.46 g/mol (approximately)
Mass of HCl = Number of moles × Molar mass = 0.1135 moles × 36.46 g/mol ≈ 4.16 grams
Therefore, approximately 4.16 grams of hydrochloric acid reacted.