Posted by Huey on Tuesday, August 28, 2012 at 11:03pm.
is your function
y = e^x + 4
or
y = e^(x+4) ????
I will assume the first
V = π∫(e^x + 4)^2 dx from 0 to .3
= π∫(e^(2x) + 8e^x + 16) dx
= π[(1/2)e^(2x) + 8e^x + 16x] from 0 to .3
= π( (1/2)e^.6 + 8e^.3 + 16(.3) - ((1/2)e^0 + 8e^0 + 0) )
= π(16.5099 - 8.5) = 25.1639
you better check my arithmetic, it has been failing me lately
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