Posted by Mike on .
Put the function P= 35(1.3)^t in the form P0ekt When written in this form, you have:
K=
P0=

Math 
bobpursley,
at t=0, P=35, so Po is 35
P=35 e^kt
P=35(1.3)^t
dividing equations..
1=e^kt/(1.3)^t
or
1.3^t=e^kt
taking ln of each side
t*ln(1.3)=kt
k=ln(1.3)