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August 30, 2014

August 30, 2014

Posted by **dave** on Tuesday, August 28, 2012 at 5:59pm.

(y^3-3y)/(y^2-9)divided by

(y^2-7y-30)/(y^2+6y+9)

Please help!

- Algebra -
**Henry**, Thursday, August 30, 2012 at 11:10pm(y^3-3y)/(y^2-9)*(y^2+6y+9)/(y^2-7y-30)=

(y(y^2-3)/(y+3)(y-3))*(y+3)(y+3)/(y+3)(y-10)=((y^2-3)/(y-3)*1/(y-10)=

(y^2-3)/(y-3)(y-10)

NOTE: All "(y+3)s" cancelled.

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