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March 28, 2017

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divide and simplify
(y^3-3y)/(y^2-9)divided by
(y^2-7y-30)/(y^2+6y+9)

Please help!

  • Algebra - ,

    (y^3-3y)/(y^2-9)*(y^2+6y+9)/(y^2-7y-30)=
    (y(y^2-3)/(y+3)(y-3))*(y+3)(y+3)/(y+3)(y-10)=((y^2-3)/(y-3)*1/(y-10)=
    (y^2-3)/(y-3)(y-10)

    NOTE: All "(y+3)s" cancelled.

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