Posted by dave on .
divide and simplify
(y^33y)/(y^29)divided by
(y^27y30)/(y^2+6y+9)
Please help!

Algebra 
Henry,
(y^33y)/(y^29)*(y^2+6y+9)/(y^27y30)=
(y(y^23)/(y+3)(y3))*(y+3)(y+3)/(y+3)(y10)=((y^23)/(y3)*1/(y10)=
(y^23)/(y3)(y10)
NOTE: All "(y+3)s" cancelled.