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September 16, 2014

September 16, 2014

Posted by **samantha** on Tuesday, August 28, 2012 at 5:49pm.

Graph both functions on the same coordinate plane

f(x)=4+e^-x/3

please help me! show steps also, if i an just given an answer that wont help me! thanks in advance!!!

- college algebra -
**bobpursley**, Tuesday, August 28, 2012 at 5:59pmI am not exactly certain of your function, I think it is this:

y=(4+e^-x)/3

e^-x=3y-4

take ln of each side

-x= ln(3y-4)

then swap variables

y=-ln(3x-4) which is the inverse function.

- college algebra -
**Bree**, Tuesday, August 28, 2012 at 6:03pmno thats not it, i am not sure how to show it on here but the -x/3 is on the side of the e. like if you had 2^3 it would be, (2)(2)(2). that is what the e^-x/3 should represent. if this makes sense

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