Posted by Anonymous on Tuesday, August 28, 2012 at 3:15pm.
since any side is less than the sum of the other two sides,
x+y > 5 (duh)
x+5 > y
y+5 > x
lots of possible solutions:
5,11,9
5,13,13
and more
values of x could be 11, 12, or 13
values of y could be 9, 10, 11, 12 or 13
now overthinking the problem:
To have a triangle:
1. x+y > 5
2. x+5 > y ----> x-y > -5 or y-x < 5
3. y+5 > x ----> y-x > -5
from #2 and #2 we can see that
-5 < y-x < 5
so make 3 columns
5_x__y_(y-x)
5 11 9
5 11 10
5 11 11
5 11 12
5 11 13
5 12 9
5 12 10
..
5 12 13
5 13 9
..
5 13 13
in short, the x could be 11, 12 or 13
the y could be 9, 10, 11, 12, or 13
so the number of triangles for sides labeled x , y and 5 is 3(5) or 15
However, triangles 5 , 12, 13 and 5, 13, 12 are the same triangle
there are 3 such duplicated pairs, so
the actual number of triangles possible is 15-3 = 12
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