Posted by **StudentD** on Tuesday, August 28, 2012 at 2:13pm.

Students in the psychology department consume an average of 5 cups of coffee per day with a standard deviation of 1.75 cups. The number of cups of coffee consumed is normally distributed.

• What proportion of students consume an amount equal to or less than 6 cups a day?

• How many cups would an individual at the 80th percentile drink?

- Statistiscs -
**MathGuru**, Tuesday, August 28, 2012 at 7:17pm
Use z-scores.

Formula:

z = (x - mean)/sd

In the first part, find z.

z = (6 - 5)/1.75

Calculate, then use a z-table to find the proportion.

In the second part, find z using a z-table for the 80th percentile. Plug into the formula, along with mean and standard deviation. Solve for x.

I hope this will help get you started.

- Statistiscs -
**StudentD**, Wednesday, August 29, 2012 at 11:51am
z = (6 - 5)/1.75 = 0.57

.2157+.50= 0.7157x100=71.57%

i.e 71.57%

In the second part, find z using a z-table for the 80th percentile. Plug into the formula, along with mean and standard deviation. Solve for x.

z = (x - mean)/sd

z (sd)= X-mean

z (sd)+mean= X

0.20= (X-5)/0.57

(0.20 x 0.57)+ 5= 5.11

b)= 5.11?

The closest in the table for 80th percentile is z=0.20 or 0.21 if I am looking at the right place? Is the above correct by any chance?

Thanks

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