ODE
posted by
mo on
.
what is the laplace transform of
5/2.e^t3/2.e^t

ODE 
Steve,
L{e^t} = 1/(s1)
L{e^t} = 1/(s+a)
L is a linear transform, so
L{5/2.e^t3/2.e^t} = 5/2 L{e^t}  3/2 L{e^t}
= 5/2 * 1/(s1)  3/2 * 1/(s+1)
= (s+4)/(s^21)

ODE 
mo,
compute the inverse laplace transform 2S^2+13S+5/(s+3)(s1)^2
i got 3e^t+5e^t+3e^t, not sure it correct