I was assiged a 51 question assigment today and its due tomorrow.I'm having a hard time with the following question:

"If angle BFA=3r+12 and angle DFE=-8r+210,find angle AFE".
PLEASE HELP!!!!

with no diagram to refer to, it's hard to say. Better describe the relative placements of the points.

r=26 r=15

To find angle AFE, we need to use the given equations for angles BFA and DFE. Let's break it down step by step:

1. Start with the given equation for angle BFA: angle BFA = 3r + 12.

2. Similarly, we have the equation for angle DFE: angle DFE = -8r + 210.

3. We know that angles BFA and AFE are adjacent angles with a common vertex F. Adjacent angles add up to 180 degrees.

4. So, we can set up the equation: angle BFA + angle AFE = 180 degrees.

5. Substitute the value of angle BFA from step 1 into the equation: (3r + 12) + angle AFE = 180.

6. Now, let's solve for angle AFE. Subtract 3r and 12 from both sides of the equation: angle AFE = (180 - 3r - 12).

7. Next, we need to substitute the value of angle DFE from step 2 into the equation: angle AFE = (180 - 3r - 12) = (180 - (-8r + 210) - 12).

8. Simplify the expression for angle AFE: angle AFE = 180 - 3r - 12 = 180 + 8r - 210 - 12.

9. Combine like terms: angle AFE = 8r - 42.

So, the measure of angle AFE is given by the equation 8r - 42. Substitute the value of 'r' into this equation to find the specific angle AFE.