A ball bounces back .06 of its height on every bounce. If a ballistic dropped from 200feet, how high does it bounce on the fifth bounce? Round to nearest tenth.
200*.06^5 = .0001555 ft
Not much of a bouncer. You sure you meant .06, and not .94?
I didn't write the question- doesn't make much sense
To find the height of the ball on the fifth bounce, we need to calculate the height after each bounce and iterate through each bounce.
Let's start by calculating the formula for the height after each bounce. Since the ball bounces back 0.06 of its height, we can multiply the previous bounce's height by 0.06 to get the height of the next bounce:
Height after each bounce = Previous bounce's height * 0.06
Now, let's calculate the height after each bounce:
1st bounce: Height = 200 feet (initial drop)
2nd bounce: Height = 200 * 0.06 = 12 feet
3rd bounce: Height = 12 * 0.06 = 0.72 feet
4th bounce: Height = 0.72 * 0.06 = 0.0432 feet
5th bounce: Height = 0.0432 * 0.06 = 0.002592 feet
Since we need to round to the nearest tenth, the height of the ball on the fifth bounce is approximately 0.0026 feet.