Homework Help: Physics

Posted by Lianne on Sunday, August 26, 2012 at 9:22pm.

A 10 kg block sits on a flat surface whose μs=0.60 and whose μk is 0.40

a. What horizontal force is required to get the block move?

b.If we continue to apply the same force as in part a. what will the blocks acceleration be?

In the answer:
force=.6*mg to move
net force=ma
first force-.6mg=ma solve for a

My question:

what is the first force??... should i subtract it to .6mg?

thanks.

Physics - Elena, Monday, August 27, 2012 at 2:44am
(a) F=F(fr) = μ(s) •N=
= μ(s) •m•g=0.6•10•9.8=58.8 N

(b) ma=F-F1(fr) =
=F- μ(k) •N= F- μ(k) •m•g,
a = (F/m) - μ(k)•g= (58.8/10) – 0.4•9.8 =
=5.88-3.92= 1.96 m/s²

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