Homework Help: physics

Posted by Anonymous on Sunday, August 26, 2012 at 4:38pm.

Two arrows are shot vertically upward. The second arrow is shot after the first one, but while the first is still on its way up. The initial speeds are such that both arrows reach their maximum heights at the same instant, although these heights are different. Suppose that the initial speed of the first arrow is 37.5 m/s and that the second arrow is fired 1.66 s after the first. Determine the initial speed of the second arrow.

physics - Elena, Monday, August 27, 2012 at 3:08am
The first arrow moved during the time interval ‘t’ to its highest point where its velocity is zero
v=v1-g•t1, v=0 =>
t1=v1/g =37.5/9.8 =3.83 s.
The second arrow moves during t2= 3.83-1.66 =2.17 s.
v =v2 - g•t2, v=0 =>
v2= g•t2=9.8•2.17 =21.27 m/s.

Answer this Question

Related Questions

physics - Two arrows are shot vertically upward. The second arrow is shot after ...
Physics - Two arrows are shot vertically upward. The second arrow is shot after ...
Physics - Three arrows are shot at different angles. A red arrow is shot at ...
physics - An arrow is short vertically upward with an initial speed of 25m/s. ...
physics - An arrow is shot verticaaly upward. Two seconds later, it is at a ...
Physics - Two particles Q and P are shot up vertically.P was first shot with ...
physics - An arrow is shot vertically upward and then 2.15 s later passes the ...
Physics - An arrow was shot vertically upward at a velocity of 50.0 m/s. What ...
physics - Marie shoots an arrow vertically upward at a sandhill crane. If the ...
physics - Marie shoots an arrow vertically upward at a sandhill crane. If the ...

For Further Reading

First Name:
School Subject:
Answer: