Posted by gin on Sunday, August 26, 2012 at 3:34pm.
Part A
Distance = 29•(2•23) = 1334 m
Displacement =0 (he started and finished at the same point)
Average velocity= displacement/time = 0
Average speed = distance/time = 1334/2.5•3600=0.148 m/s
Part B
Distance 29.5•(2•23)= 1357 m.
Displacement =23 m
Average velocity= displacement/time =23/2.5•3600 =0.00256 m/s
Average speed = distance/time = 1357/2.5•3600=0.1508 m/s
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