Posted by ash on Sunday, August 26, 2012 at 12:40pm.
i changed it too
f(1.9)= 10.186
f(1.5)= -2.344
so, the IVT says that if f(x) is continuous, it must take on all values between 10.186 and -2.344.
That includes 0, so there is the proof.
BTW, you values for f are correct.
so i am right? x and y?
x=-2.344
y=10.186
it was continuous, but they wanted it rounded to three decimal places
I wouldn't call your values x and y.
You have two x-values: 1.5 and 1.9
and two values for f(x) or y: -2.344 and 10.186
and, as I said, given those two values for x, your two y values are correct to 3 places.
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