Posted by serin on Sunday, August 26, 2012 at 11:14am.
correct if you denominator is x+7
(the way you typed it, the denominator is x )
I would write the answer as
{x|x ∈ R , x ≠ -7}
reiny the way you typed it is not an option and yes x+7 is the denominator
{x|x 0 and x -7}
is the closet to it
{x|x 0 and x -7}
sorry the not equal signs didnt post
Too bad my answer is not an option.
In the domain it should be stated that x can be any real number except -7
there are different ways to say this, my statement is just one of those ways.
To say {x|x is not equal to -7} does not tell the whole story and in my opinion is insufficient.
While technically you are correct, Reiny, I'd have to take the answer in the likely context. This is obviously Algebra II or some such, and we are likely dealing only with real, or maybe complex numbers.
So, restricting our "domain", as it were, to that area, x not equal to 7 pretty much sums it up.
If the problem was multiple choice, then I'd have picked the answer serin gave.
Otherwise, maybe
x real and ≠ 7
or
{x|x real , x ≠ -7}
would have provided the required details.
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