Posted by greeny on Sunday, August 26, 2012 at 1:16am.
15g of Fe is 15/55.845 = 0.2686 moles
Each mole of Fe requires 1 mole of Fe2O3 and 2 moles of Al.
mol wt Fe2O3 = 2*55.845+3*15.999 = 159.687
mol wt Al = 26.982
so, we need
.2686*159.687 = 42.9g Fe2O3
.2686*2*26.982 = 14.5g Al
mol wt Al2O3 = 2*26.982+3*15.999 = 101.961
so, we get .2686*101.961 = 68.9g Al2O3
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