Posted by Anonymous on Sunday, August 26, 2012 at 12:36am.
Apparently you have already answered question 1. If not, see the "related Question" below.
Question 2:
If the ball starts at a height of Ho = 44 m, if loses the available kinetic energy until it reaches the maximum height Hmax
g*Ho + Vo^2/2 = g*Hmax
(Hmax-Ho)= Vo^2/(2g) = 45.9 m
Hmax = 89.9 m
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