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October 2, 2014

October 2, 2014

Posted by **Rick** on Saturday, August 25, 2012 at 7:11pm.

"Rays PQ and QR ae perpendicular.Point S lies in the interior of angle PQR.If angle PQS!=4+7a and angle SQR=9+4a,find angle PQS and angle SQR.

PLEASE HELP!!!!

- geometry -
**Damon**, Saturday, August 25, 2012 at 7:16pm4 + 7 a + 9 + 4 a = 90 degrees

13 + 11 a = 90

11 a = 77

a = 7

PQS = 4 + 49

SQR = 9 + 28

- geometry -
**Rick**, Saturday, August 25, 2012 at 11:09pmThank you so much!!!!!

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