I not sure what formula to use for KE or how to find the mass for the equation.

Water is flowing through a 2-inch diameter pipe with a velocity of 3 ft/s.
Part A
What is the kinetic energy of the water in (ft)(lbf)/(lbm)? (lbf) pound force (lbm) pound mass
Part B
What is the flow rate in gal/min?

A. find area of pipe (PI*r^2).

volume water= area*velocity (watch units, I recommend covert ara to ft^2)

mass water=volumewater*densitywater

KE=1/2 m v^2

b. just convert wha tyou have given.

Angel, I have to say it bothers me that your teacher is wasting time teaching you all these different systems, when what you need to be concentrating on is the concepts in the SI measurement system. He probably disagrees.

If you cannot figure this out on your own then you do not need to be a Chemical Engineer. Pick a different major. Question 2.2.10 Basic Principles and Calculations In Chemical Engineering

Those you doubt those who need help can shut up! i am glad you asked this! You are learning and so am I. And the reason that the teacher are teaching this particular question is because American Engineers have to deal with both AE Units and SI and we need to know how to convert both (quickly) Practice Practice Practice

18.54lb.ft^2/sec^2

To calculate the kinetic energy (KE) of an object, you can use the formula: KE = (1/2) * m * v^2, where m represents the mass of the object and v represents its velocity.

In order to find the mass for the equation, you can use the density formula: density = mass/volume. However, since the mass is not given directly for the water flowing through the pipe, we need to use other known information to find it.

For Part A:
1. Start by finding the cross-sectional area of the pipe.
The diameter of the pipe is given as 2 inches. To convert inches to feet, divide by 12: 2 inches / 12 = 0.1667 ft.
The radius of the pipe is half of the diameter: 0.1667 ft / 2 = 0.0833 ft.
The formula to calculate the cross-sectional area of a circle is: A = π * r^2, where π is a constant (approximately 3.14159).
Therefore, the cross-sectional area is: A = 3.14159 * (0.0833 ft)^2 = 0.0216 ft^2.

2. Calculate the mass of the water flowing through the pipe.
We can use the formula: mass = density * volume.
Assuming the fluid is water, which has a density of 62.4 lbm/ft^3, we can find the volume of the water flowing through the pipe.
Since velocity represents the speed at which water flows, we can express it as: velocity = volume/time.
Rearrange the formula to find volume: volume = velocity * time.
Let's assume a time frame of 1 second, so the volume of water flowing through the pipe in 1 second will be equal to the area of the cross-section of the pipe times the velocity.
Therefore, the volume is: volume = 0.0216 ft^2 * 3 ft/s = 0.0648 ft^3.

Now, use the density formula to find the mass: mass = 62.4 lbm/ft^3 * 0.0648 ft^3 = 4.03 lbm.

3. Calculate the kinetic energy.
Insert the values we found into the KE formula:
KE = (1/2) * 4.03 lbm * (3 ft/s)^2 = 18.27 ft·lbf/lbm.

For Part B:
To find the flow rate, we can use the formula: flow rate = volume / time.
1. We already calculated the volume of water flowing through the pipe in 1 second as 0.0648 ft^3.
2. Assume a time frame of 1 minute, which is equal to 60 seconds.
Therefore, the flow rate will be: flow rate = 0.0648 ft^3 / 60 s = 0.00108 ft^3/s.
3. Convert the flow rate to gallons per minute (gal/min).
Since 1 cubic foot is approximately equal to 7.4805 gallons, we can use the conversion factor:
flow rate = 0.00108 ft^3/s * 7.4805 gal/ft^3 * 60 s/min = 0.482 gal/min.

Therefore, the flow rate of the water through the pipe is approximately 0.482 gal/min.