Balancing Equation
Al2C3O3 + H3PO4 --> AlPO4 + CO2 + H2O
You sure you typed it right?
Each Al2C3O3 + 2H3PO4 --> 2AlPO4 plus H6C3O3
We can use up the C in 3CO2, but that leaves us O3 short
We can use up the H6O3 in 3H2O, but that leaves us with C3 extra.
Every time I try to fudge on the left, I have to keep the same 1:2 ratio between Al2C3O3 and H3PO4.
I never heard of Al2C3O3. It could be Al2(CO3)3 = Al2C3O9??
I think the question that my friend gave me is wrong. I have been trying to answer this for almost 3 hours last night
To balance the equation, we need to make sure that the number of atoms of each element is the same on both sides of the equation. Here's how you can balance the given equation:
1. Start by counting the number of each type of atom on both sides of the equation.
Al2C3O3 + H3PO4 --> AlPO4 + CO2 + H2O
On the left side, we have:
- 2 atoms of aluminum (Al)
- 3 atoms of carbon (C)
- 9 atoms of oxygen (O)
- 3 atoms of hydrogen (H)
- 1 atom of phosphorus (P)
On the right side, we have:
- 1 atom of aluminum (Al)
- 1 atom of phosphorus (P)
- 4 atoms of oxygen (O)
- 2 atoms of carbon (C)
- 3 atoms of hydrogen (H)
2. Start with the element that appears in the smallest number of atoms on one side of the equation. In this case, it's phosphorus (P). To balance it, we need to put a coefficient of 3 in front of H3PO4 on the left side:
Al2C3O3 + 3H3PO4 --> AlPO4 + CO2 + H2O
Now we have:
- 3 atoms of phosphorus (P) on both sides.
3. Next, balance the aluminum (Al) atoms. We need to place a coefficient of 2 in front of AlPO4 on the right side:
Al2C3O3 + 3H3PO4 --> 2AlPO4 + CO2 + H2O
Now we have:
- 2 atoms of aluminum (Al) on both sides.
4. Now, balance the carbon (C) atoms. We need to put a coefficient of 3 in front of CO2 on the right side:
Al2C3O3 + 3H3PO4 --> 2AlPO4 + 3CO2 + H2O
Now we have:
- 3 atoms of carbon (C) on both sides.
5. Finally, balance the oxygen (O) and hydrogen (H) atoms. There are 12 oxygen atoms on the left side and only 4 on the right side, so we need to add a coefficient of 6 in front of H2O on the right side:
Al2C3O3 + 3H3PO4 --> 2AlPO4 + 3CO2 + 6H2O
Now we have:
- 12 atoms of oxygen (O) on both sides.
In conclusion, the balanced equation is:
Al2C3O3 + 3H3PO4 --> 2AlPO4 + 3CO2 + 6H2O