Wednesday
March 29, 2017

Post a New Question

Posted by on .

a body (A) is moving with a speed of 250m/s in the positive x-direction, collides with body (B) initially at rest and having the same mass as (A). after collision the speed of body (A) is 100m/s making 30 degree with the horizontal. the speed and direction of body (B) after the collision is:

a) 50 m/s f= 71 degree
b)25 m/s f= 30 degree
c) 171 m/s f= 17 degree
d) 342 m/s f= 34 degree

  • Physics - ,

    assume each mass is 1 kilogram
    momentum before = momentum after
    i is x direction, j is y direction
    before = 250 i and 0 j
    after
    Ai = 100 cos 30
    Aj = 100 sin 30 = 50
    Since Aj + Bj = 0,
    Bj = -100 sin 30 = -50

    250 = Ai + Bi = 100 * .866 + Bi
    250 = 86.6 + Bi
    Bi = 163

    V^2 = 50^2 +163^2
    V = 171

    tan theta = -50/163 = -17 deg

    so c

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question