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August 31, 2014

August 31, 2014

Posted by **Bella** on Friday, August 24, 2012 at 9:40pm.

degree 5; zeros -5;-i; -5+i

- college alg -
**drwls**, Friday, August 24, 2012 at 10:02pmIf x = -i and x = -5 +i are roots, so must be x = i and x = -5 -i.

A(x+5)(x-i)(x+i)(x+5+i)(x+5-i)= 0

is a polynomial with those roots, where A is any constant.

Let's set A = 1.

That can be rewritten

(x+5)(x^2 +1)(x^2 +10x +25 +1)= 0

or

(x^3 +5x^2 +x +5)(x^2 +10x +26) = 0

Multiply that out for the full fifth order polynomial.

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