college alg
posted by Bella on .
form a polynomialf(x) with real coefficients, having the given degree and zeros
degree 5; zeros 5;i; 5+i

If x = i and x = 5 +i are roots, so must be x = i and x = 5 i.
A(x+5)(xi)(x+i)(x+5+i)(x+5i)= 0
is a polynomial with those roots, where A is any constant.
Let's set A = 1.
That can be rewritten
(x+5)(x^2 +1)(x^2 +10x +25 +1)= 0
or
(x^3 +5x^2 +x +5)(x^2 +10x +26) = 0
Multiply that out for the full fifth order polynomial.