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September 30, 2014

September 30, 2014

Posted by **Bella** on Friday, August 24, 2012 at 9:02pm.

f(x)= x^3-6x^2+21x-26

- college algebra -
**drwls**, Friday, August 24, 2012 at 10:15pmWhat do you mean by "complex zeroes"? You must mean the complex values of x that result in a zero for f(x).

Inspection indicates that x = 2 is a root, so (x-2) is a factor. Divide f(x) by x-2 for the remaining quadratic factor, which should be x^2 -4x +13.

That will have two complex roots. Find them.

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