Posted by jeffrey on Friday, August 24, 2012 at 8:05pm.
If you had given some numbers it would have been easier; however, here is the procedure.
1. Write the equation and balance it.
CH3NH3 + HCl ==> CH3NH3Cl
2. mols HCl used = M HCl x L HCl = ?
3. mols CH3NH2 = same as mols HCl (since the equation is 1 mol CH3NH2 to 1 mol HCl).
4. M CH3NH2 = moles CH3NH2/L CH3NH2.
Done.
thanks, sorry,
10ml of the unknown mixture was titrated
methyl orange was used
it took 7.5ml of 1M HCl (.0074Mol ?)
so this means .00074Mol CH3NH2 / ml ?
Related Questions
chemistry - 31.0mL sample of LiOH, concentration unknown, is titrated with .52 M...
Chemistry-Titration - Acid (Unknown) Solution: HCL Molar Ratio: 1:1 Volume:20 ml...
chemistry - if 50.0 mLs of HCl of unknown concentration is titrated to ...
chemistry - if 50.0 mLs of HCl of unknown concentration is titrated to ...
Chemistry - A sample of Hydrochloric Acid (HCl) has a concentration of 5.00 %(m/...
Chemistry - a 15.00mL sample of NaOH was titrated to the stoichiometric point ...
Chemistry - It requires 17.9 mL of 0.120 M KOH to titrate 78.0 mL of an HCl ...
Chemistry - A student completes titration by adding 12.0 mL of NaOH(aq) of an ...
chemistry - A student completes a titration by adding 12.0 milliliters of NaOH(...
Chemistry - A student completes a titration by adding 12.0 milliliters of NaOH(...
For Further Reading