Posted by **israa** on Friday, August 24, 2012 at 4:26pm.

two cars start on opposite sides of a circular track. One car has a speed of 0.015 rad/s;the other car has a speed of 0.012 rad/s. If the cars start p radians apart, calculate the time it takes for the fatser car to catch up with the slower car.

the answers :1050s (17.5 min) but i just can't see how its done, plz help me

## Answer This Question

## Related Questions

- Math - Two cars run at constant speeds around a one-mile racetrack. If the cars ...
- Algebra - Two cars start at the same point at Alexandria, verginia, and travel 2...
- Algebra - Two cars start at the same point at Alexandria, verginia, and travel ...
- Physics - Two cars start from the same place at the same time. After two hours, ...
- physics - Two people start at the same place and walk around a circular lake in ...
- Physics - Two people start at the same place and walk around a circular lake in ...
- physics - Two people start at the same place and walk around a circular lake in ...
- Physics - Two people start at the same place and walk around a circular lake in ...
- Physics - Two cars are initially 10.5 km apart on a straight road. If the cars ...
- Phsyics - Two cars start from the same place at the same time. After two hours, ...

More Related Questions