physics
posted by israa .
two cars start on opposite sides of a circular track. One car has a speed of 0.015 rad/s;the other car has a speed of 0.012 rad/s. If the cars start p radians apart, calculate the time it takes for the fatser car to catch up with the slower car.
the answers :1050s (17.5 min) but i just can't see how its done, plz help me

the quicker car gains on the slower car at a rate of 0.003 rad/s
if they start pi radians apart, then the time needed is pi/.003 = 1047.19 sec.
That's pretty close to 1050 sec.