Posted by Mountain Scott on .
Write the equation of a circle in standard Find the center, radius intercepts and graph the circle. .........x^2+y^212x4y+36=0

College Algebra 
Damon,
x^2 12 x = y^2 + 4 y 36
x^2 12 y + 36 = y^2 + 4 y
(x6)^2 = y^24y
(x6)^2 + 4 = y^2  4 y + 4
(x6)^2 + 4 = (y2)^2
(x6)^2 + (y2)^2 = 4
center at (6,2) radius 2
you do the rest