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July 22, 2014

July 22, 2014

Posted by **Ari** on Thursday, August 23, 2012 at 8:15pm.

??

- Math -
**Reiny**, Thursday, August 23, 2012 at 10:50pm(54x^17)^(1/3)

= (27x^15)^(1/3) (2x^2)^(1/3)

= 3x^5 (2^(1/3) x^(2/3)

- Math -
**Samantha**, Friday, September 7, 2012 at 8:56amFirst I factor 54.

5 4

| |

9 6

|\ \ \

3 3 3 2

{3 3 3} group of threes that can be out of cubed root

Because there are three threes I take them out of the cubed root (# = im going to consider this as my cubed root button) turning #54x^17 into 3#2x^17

Now we factor x^17:

there are 5 groups of 3s in 17 so we would take those out leaving x^2 in the root.

3#2x^17 turns into 3x^5 # 2x^2

Then this simplified is therefore

3x^5 cube root of 2x^2

- Math -
**Samantha**, Friday, September 7, 2012 at 8:56amFirst I factor 54.

5 4

| |

9 6

|\ \ \

3 3 3 2

{3 3 3} group of threes that can be out of cubed root

Because there are three threes I take them out of the cubed root (# = im going to consider this as my cubed root button) turning #54x^17 into 3#2x^17

Now we factor x^17:

there are 5 groups of 3s in 17 so we would take those out leaving x^2 in the root.

3#2x^17 turns into 3x^5 # 2x^2

Then this simplified is therefore

3x^5 cube root of 2x^2

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