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Starting with an initial speed v0, a mass m slides down a curved frictionless track (a shown in the figure below), arriving at the bottom with a speed v. From what vertical elevation h did it start?

  • physics -

    (PE+KE)initial = (PE+KE)final
    mgh + mv0^2/2 = 0 + mv^2/2
    => h = (v^2-v0^2)/2g

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