Posted by Kirk on .
ok so having trouble with this have tried and trie but can seeem to come up with tthe answer. d/(1d)^2=(d+1)^2  1/d
the answer we were given is d^52d^32d^2+3d1=0

Math 
Reiny,
d/(1d)^2=(d+1)^2  1/d
the LCD = d(1d)^2
so multiply each term by that
d^2 = d(1d)^2 (d+1)^2  (1d)^2
d^2 + (1d)^2 = d[(1d)(1+d)]^2
d^2 + (1d)^2 = d[(1d^2]^2
d^2 + 1  2d + d^2 = d(1  2d^2 + d^4)
d^2 + 1  2d + d^2 = d  2d^3 + d^5
d^5  2d^3  2d^2 + 3d  1 = 0 as shown in your answer