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September 20, 2014

September 20, 2014

Posted by **Kirk** on Wednesday, August 22, 2012 at 9:14pm.

the answer we were given is d^5-2d^3-2d^2+3d-1=0

- Math -
**Reiny**, Wednesday, August 22, 2012 at 11:22pmd/(1-d)^2=(d+1)^2 - 1/d

the LCD = d(1-d)^2

so multiply each term by that

d^2 = d(1-d)^2 (d+1)^2 - (1-d)^2

d^2 + (1-d)^2 = d[(1-d)(1+d)]^2

d^2 + (1-d)^2 = d[(1-d^2]^2

d^2 + 1 - 2d + d^2 = d(1 - 2d^2 + d^4)

d^2 + 1 - 2d + d^2 = d - 2d^3 + d^5

d^5 - 2d^3 - 2d^2 + 3d - 1 = 0 as shown in your answer

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