Friday

November 28, 2014

November 28, 2014

Posted by **Kirk** on Wednesday, August 22, 2012 at 9:14pm.

the answer we were given is d^5-2d^3-2d^2+3d-1=0

- Math -
**Reiny**, Wednesday, August 22, 2012 at 11:22pmd/(1-d)^2=(d+1)^2 - 1/d

the LCD = d(1-d)^2

so multiply each term by that

d^2 = d(1-d)^2 (d+1)^2 - (1-d)^2

d^2 + (1-d)^2 = d[(1-d)(1+d)]^2

d^2 + (1-d)^2 = d[(1-d^2]^2

d^2 + 1 - 2d + d^2 = d(1 - 2d^2 + d^4)

d^2 + 1 - 2d + d^2 = d - 2d^3 + d^5

d^5 - 2d^3 - 2d^2 + 3d - 1 = 0 as shown in your answer

**Answer this Question**

**Related Questions**

English - I have to write an essay on the theme of the short story "All is clam...

Functions - What's the best way to solve functions? I can do basic ones, but ...

1984 - 1.What is Orwell's version of history prior to his own time? My answer: I...

Algergra - I am stumped! I have been working on these problems for the longest ...

Functions - more info - Sorry, I forgot to enter all the info before. Below is ...

Math 141 - I am having trouble with this problem. perform the indicated ...

Algebra - (3X+1)/(3)-(3/2)=(1-X)/(4) I am having trouble simplifying the ...

Math - I am having trouble figuring the appropriate expression for this problem...

Physical Chemistry - Calculate the concentrations of each of the following ...

Math - I don't have any specific problems I need help with, but I'm a bit ...