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August 1, 2014

August 1, 2014

Posted by **TB** on Wednesday, August 22, 2012 at 12:32pm.

1 )-3

-----

xy^3 )-3

everything times the negative power of 3 help please

- intermediate algebra -
**Steve**, Wednesday, August 22, 2012 at 2:32pm(xy^3)^-3 = x^-3 * (y^3)^-3 = x^-3 * y^-9 = 1/x^3 * 1/y^9 = 1/(x^3 y^9)

or, doing it the other way,

(xy^3)^-3 = 1/(xy^3)^3 = 1/(x^3 y^9)

Not sure what the initial 1)-3 is all about, but what I posted above should get you going.

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