suppose the glider is initially at rest at x=0, with the spring unstretched. You then apply a constant force in the +x direction with magnitude 0.610 N to the glider. what is the glider's velocity when it has moved 0.100m?

Work equal to F*X = 0.061 Joules will have been performed on the glider.

You need to knmow the glider's mass, and what the spring is doing, to calculate the glider's velocity.

To find the glider's velocity when it has moved 0.100m, you can use Newton's second law of motion:

F = m * a

where F is the force applied, m is the mass of the glider, and a is the acceleration of the glider.

Since the force applied is constant and in the +x direction, the acceleration will also be constant. To find the acceleration, you can use Hooke's law, which relates the force exerted by a spring to the displacement from its equilibrium position:

F = -k * x

where F is the force exerted by the spring, k is the spring constant, and x is the displacement from the equilibrium position.

In this case, the spring is initially unstretched, so the force exerted by the spring is zero. Therefore, we have:

0.610 N = m * a

To find the acceleration, we need to know the mass of the glider. Let's assume the mass is 1 kg.

0.610 N = 1 kg * a

Solving for a:

a = 0.610 N / 1 kg
a = 0.610 m/s^2

Now, we can use the constant acceleration equation to find the final velocity of the glider when it has moved 0.100m:

v^2 = u^2 + 2 * a * s

where v is the final velocity, u is the initial velocity (which is 0 m/s since the glider is initially at rest), a is the acceleration, and s is the displacement.

Plugging in the values:

v^2 = (0 m/s)^2 + 2 * (0.610 m/s^2) * (0.100 m)
v^2 = 0 + 0.122 m^2/s^2
v = sqrt(0.122 m^2/s^2)
v ≈ 0.349 m/s

Therefore, the glider's velocity when it has moved 0.100m is approximately 0.349 m/s.