# Algebra

posted by on .

I need help with this like really badly sooo yeahhhh:)
here it is:
Hugo withdrew some money from his bank account. He spent one third of the money for gasoline. Then he spent half of what was left for a haircut. He bought lunch for \$6.55. When he got home,he had \$13.45 left. How much money was withdrawn from the bank?

• Algebra - ,

BTW!!! I need it explained on like how you figured it out because i have another ? like it and i want to try and do that one on my own!!! THX!
;)

• Algebra - ,

started with x dollars
spend (1/3)x for gas, leaving him (2/3)x
spend (1/2) of (2/3)x on haircut
leaving him with (2/3)x - (1/2)(2/3)x or (1/3)x
after lunch he had (1/3)x - 6.55

so (1/3)x - 6.55 = 13.45
(1/3)x = 20
x = 60

check:
spend 1/3 of that or 20 on gas
leaving him with 40
spend 1/2 of that or 20 on haircut, leaving him with 20
spend 6.55 on lunch, leaving him with 13.45
checks out!

(Time to update those prices,
\$20 for gas , not going too far with that
\$6.55 for lunch, but \$20 for haircut? )

• Algebra - ,

Thank You Reiny i see what you did there :) i was confused on some of the things but i understand how to do that stuff now!
Thanks Again!,
Emily

• Algebra - ,

You could do this by working backwards if you don't know algebra:

before lunch he must have had 13.45 + 6.55 or \$20
this was half of what he had before the haircut, so he must have had \$40 before the haircut
the \$40 must be 2/3 of what he had before getting gas, since he spent 1/3 on gas
so 3/3 must have been \$60