Wednesday

July 23, 2014

July 23, 2014

Posted by **Emily** on Wednesday, August 22, 2012 at 8:38am.

here it is:

Hugo withdrew some money from his bank account. He spent one third of the money for gasoline. Then he spent half of what was left for a haircut. He bought lunch for $6.55. When he got home,he had $13.45 left. How much money was withdrawn from the bank?

- Algebra -
**Emily**, Wednesday, August 22, 2012 at 8:43amBTW!!! I need it explained on like how you figured it out because i have another ? like it and i want to try and do that one on my own!!! THX!

;)

- Algebra -
**Reiny**, Wednesday, August 22, 2012 at 8:45amstarted with x dollars

spend (1/3)x for gas, leaving him (2/3)x

spend (1/2) of (2/3)x on haircut

leaving him with (2/3)x - (1/2)(2/3)x or (1/3)x

after lunch he had (1/3)x - 6.55

so (1/3)x - 6.55 = 13.45

(1/3)x = 20

x = 60

check:

start with 60

spend 1/3 of that or 20 on gas

leaving him with 40

spend 1/2 of that or 20 on haircut, leaving him with 20

spend 6.55 on lunch, leaving him with 13.45

checks out!

(Time to update those prices,

$20 for gas , not going too far with that

$6.55 for lunch, but $20 for haircut? )

- Algebra -
**Emily**, Wednesday, August 22, 2012 at 8:55amThank You Reiny i see what you did there :) i was confused on some of the things but i understand how to do that stuff now!

Thanks Again!,

Emily

- Algebra -
**Reiny**, Wednesday, August 22, 2012 at 9:17amYou could do this by working backwards if you don't know algebra:

before lunch he must have had 13.45 + 6.55 or $20

this was half of what he had before the haircut, so he must have had $40 before the haircut

the $40 must be 2/3 of what he had before getting gas, since he spent 1/3 on gas

so 3/3 must have been $60

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