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October 25, 2014

October 25, 2014

Posted by **dakota** on Tuesday, August 21, 2012 at 11:14pm.

- math -
**Reiny**, Wednesday, August 22, 2012 at 9:13amno unique solution, since you have 4 variables but only 3 equations.

To find some solutions, you could do this:

divide the 3rd by the 2nd

rt/(st) = 21/(2y)

r = 21s/(2y)

sub into the 1st

s(21s)/(2y) = 3y+1

21s^2 = 2y(3y+1)

s^2 = 2y(3y+1)/21

**s =√[2y(3y+1)/21 ]**

also t = 2y/s and r = 21/t

so you could assign any value to y and get the others

e.g. let y = 1

then s = √(8/21) = appr 6.172

then t = 3.24 and r = 6.48

so (r,s,t,y) = (6.48, .6172, 3.24, 1)

let y = 4

s = √(104/21) = appr 2.225

then t = 3.595 and r = 5.842

(r,s,t,y) = (5.842, 2.225, 3.595, 4)

I checked the above, if you store the 4 numbers in 4 separate memory locations on your calculator, the results are correct.

Without a calculator the above would be a nightmare

- Geometry -
**Madison**, Thursday, September 6, 2012 at 4:21pmIf

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