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December 18, 2014

December 18, 2014

Posted by **Unknown"** on Tuesday, August 21, 2012 at 2:19pm.

1. √x-10+4=0

Answer: x=26

2.√3x+1=7

Answer: x=16

Help With These:

3. √x+6=x

how would you solve this?

I don't get how would It?

4. √x+4 = √x-1+1

it looks similar to problem 2 but it doesn't quite have the same amount of numbers in the same spots..

So I'm stuck on how to solve it.

- Math -
**Steve**, Tuesday, August 21, 2012 at 3:35pm√(x-10) + 4 = 0

if x=26, you have

√16 + 4 = 0

which is not true.

√n is a positive value, so there is no solution.

Now, √(x-10) - 4 = 0 has solution x=26

√(3x+1) = 7

has the solution x=16 as you say.

√(x+6) = x

square both sides:

x+6 = x^2

now solve as a quadratic

x = -2 or 3

However, √4 = 2, not -2, so -2 is an extraneous solution introduced by squaring. -2+6 = 4 = (-2)^2, but √4 = 2, not -2.

same method here:

x+4 = (x-1) + 2√(x-1) + 1

4 = 2√(x-1)

16 = 4(x-1)

x = 5

check: √(5+4) = √9 = 3 = √(5-1)+1 OK

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