Posted by
Drew on
.
Fiind the area bounded by the parabola y^2 = 8x, the x axis and the line x=2

Math 
Tim,
I think the answer is 2.25V.

Math 
Steve,
a = ∫[0,2] √(8x) dx
= √8 (2/3 x^3/2) [0,2]
= 2√8/3 (2√2)
= 16/3
a = ∫[0,4] 2y^2/8 dy
= 4y  y^3/24 [0,2]
= 8  64/24
= 16/3