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July 4, 2015

July 4, 2015

Posted by **deel** on Tuesday, August 21, 2012 at 4:46am.

lim lnx/lgx

x->infinity

- math -
**Steve**, Tuesday, August 21, 2012 at 10:33amIf lg(x) = log

_{2}x, then since

lgx = lnx/ln2,

lnx/lgx = ln2 for all x.